Arrays in C# .Net

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Arrays

Arrays are of type “reference” That is even if an Array is not initialized still it holds some default values.

int a, b, c ; C = a + b; STACK

Screenshot_23

Array  X(5)       x=5000 HEAP

  Screenshot_24  

The array is a collection of homogeneous data type Arrays shares the same name with different index values Always index starts from ‘0’ Arrays will be stored in continuous memory Arrays are faster in accessing All the arrays are instance of the system. Array class

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C# supports three types of Arrays One-dimensional arrays Multidimensional arrays Jagged Arrays       

 Screenshot_25

Working with a one-dimensional array

Syntax Data type []  arr_name  = new data type [size];

 

Example Screenshot_27

  While initializing an array, size is not recommended

Example

A program to print array default rules:-

Open window forms application project Place a button Code for button 1

click

{

Int [] x = new int [2];

For  (int  I =0 ; i< arg.length ; I ++);

Message Box. Show ( x [i]+ “”);

}

Output

  Screenshot_29

Observations

The integral Array default value is Zero. Floating Array default value is Zero.

char Array default value is nothing. Bool Array default value is false.

Date time Array default value is 1/1/0001 12:00:00 AM.

Example

A program to create or get the spelling of a given number     (1…………………..999) 123…………..one hundred twenty-three Open windows forms application project Place two text boxes and a button Screenshot_30  

Code for button1

click

{

Int n = int. parse (text box 1.text);

Int I = 0;

String res = “”;

String [] ones  =  new string [] 

{ “one”, “two”, “three”, “four” “five”, “six” ………………,” nineteen”};

String [] Tens = new string []

{“ten”, “twenty”, “ninety”};

N = 426 N = 426/ 100  -à 10/3 = 3

    If (n > 99 && n < 1000)

{

I = n / 100; Res = ones [I - 1] + “hundred”; N = n % 100;

}

If (n > 19 && n < 1000)

{

I = n / 100; Res = ones [I - 1] + “hundred”;

N = n % 100;

}

If (n > 0&& n < 20)

Res =res +  ones [I - 1] ;

Text Box 2.text = res;

F5

}

Screenshot_32

Working with Multi Dimensional Arrays

Arranging a set of elements in rows and columns is called  “Multi-Dimensional Array”.

In a Multi-Dimensional Array, every row must contain the same number of elements. Multi-Dimensional Array size will be represented with no. of rows X  no. of columns If the array name is ‘X’ then x. length return a total number of elements.

Screenshot_33

get length (0) returns no. of rows get length (1) returns no. of columns syntax to declare multi – d array I0 : int [] x = new int [s]; S arrrow 20 : int [,] x = new int [s,s]; 30 : int [,,] x = new int [s,s,s];

 

Note VB supports up to 32 dimensions where as no limit in C #.NET Syntax to initialize 2 D Array   Int [,] x = new int [,] { {5,6,7,8} {9,8,7,6} {5,5,5,5} }

  Screenshot_34  

 

Example with multi dimension Array

Open windows forms application project Place a button Code for button 1

click

  {

String  s = “”;

Int [,]  x = new int [,];

{ {5, 6, 7, 8}, {9, 8, 7, 6}, {5, 5, 5, 5} };

  r=0                  c = 0 Rr=1                    c =1 c =2 c =3 message  box. Show (“Total :” + x. length) ;

message box .show  (“Rows : + x. get length  (0)”) + “ cols :”  + x. get length  (1) );

For (int  r = 0; r < x. get length  (0);r ++)

{

For (int  c = 0; c< x. get length  (0);c ++)

{

S = S + X [r,c] + “” ;

}

S= s + “/n”

}

Message Box. Show (s);

Jagged Arrays

ABC(Company) Members are working Employees   arrrow3*6arrrowvalues

Screenshot_35  

A jagged array is a collection of rows where every row may contain a different number of elements. Jagged arrays save memory. Jagged arrays are faster in accessing. Jagged arrays are also called as “Dynamic array” (run time array) Jagged array is also called an array of arrays.

Syntax Int []  [] x = new int [3] []; X [0] = new int [] {4,2,3,5,6,7} X [1] = new int [] {3,8,4,2,4}

Example Open windows forms application project Place a button Code for button 1

click

  {

Int [] []   x = new int [3][];

X [0] = new int [] {5,3,4,6,7,7};

X [1] = new int [10];

X [2] = new int []{2,3};

String  S = “”;

For  (int r  = 0;r < x.get length (0);r ++)

{

For  (int c  = 0;r < x.get length (0);c++)

{

S= s + x[ r][c] +””;

}

S =s + “/n”

}

Message Box. Show (s);  

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